LimitsLast updated: Aug 5, 2020 · PermalinkPosted in wiki#notesExperimenting with KaTeX. ∫1a2+x2 dx=1aarctanxa+c\int\frac{1}{a^2+x^2}\,dx = \frac{1}{a}\arctan{\frac{x}{a}} + c∫a2+x21dx=a1arctanax+cSubmit feedback Share on: Hacker News · Lobsters · Reddit · Twitter← PreviousMisc puzzlesNext →Differential calculus